Skip to main content

Get the list of all the files and directories

Function Use: To print all the directories in a folder/sub-folder or directory import os def get_list_or_dir(local_dir):     for dir_or_file in os.listdir(local_dir):         if os.path.isdir(dir_or_file):             path = os.path.join(local_dir, dir_or_file)             print(dir_or_file, 'This is a directory')             get_list_or_dir(path)         else:             print(dir_or_file) Path = os.getcwd() or define the path from where you need a file Function Call: get_list_or_dir(path)
Post a Comment

Printing Pattern in Python - Ep 1

How to print the below pattern in Python:

* * * *
* * * *
* * * *
* * * *

I will be showing 2 ways to print the above pattern, but there are more ways; you can explore it by practising yourself.

Before starting this i want to show you some of the trick that you should know. If you want to print same number, word or anything number of times, you can the use the below code.

>>> print(4* "Avenger ")
Avenger Avenger Avenger Avenger 

 Here i wanted to print Avenger 4 times than i just wrote 4*"Avenger " in the print statement and i got the desired output.

So, we are good to begin printing the above pattern in python.

Method 1:

 >>> n = 4
>>> for i in range(0, n):

print(n*"* ")

 * * * * 
* * * * 
* * * *
* * * * 

 I guess i don't need to explain it further, I wanted to print star in 4 times so i just wrote print(n* "* ") to print the star 4 times in a row and i ran the loop 4 times by using "for" loop.

Method 2:

 >>> n = 4
>>> for i in range(0,n):
j = 0
while j < n:
print("* ", end = "")
j += 1
print()
* * * * 
* * * * 
* * * * 

* * * * 

 Here we have used end="' ". You can follow this blogpost to learn about end parameter.

Keep reading Python an hour a day to learn simple Python tricks, tips and programme.
Labels:

Comments

Post a Comment

Popular posts from this blog

Project Euler Problem 13

This problem seems difficult at first, but once you understand it; this will prove out to be easiest of all the problems in Project Euler: I guess you will have seen the problem till now, if not then visit Project Euler 13 else scroll down for this problem. The Solution: The number mentions in the problem is of 100 line and in one line there are 50 numbers. So basically you just have to add all the 100 numbers (each number consist of 50 digits).  you will need str.split() function to do the job. num = "37107287533902102798797998220837590246510135740250 \n \ 46376937677490009712648124896970078050417018260538 \n \ 74324986199524741059474233309513058123726617309629 \n \ 91942213363574161572522430563301811072406154908250 \n \ 23067588207539346171171980310421047513778063246676 \n \ 89261670696623633820136378418383684178734361726757 \n \ 28112879812849979408065481931592621691275889832738 \n \ 44274228917432520321923589422876796487670272189318 \n \ 474514457360013064...
2 comments
Read more

Project Euler 14:Longest Collatz sequence

The Problem: The following iterative sequence is defined for the set of positive integers: n → n /2 ( n is even) n → 3 n + 1 ( n is odd) Using the rule above and starting with 13, we generate the following sequence: 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1   It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1. Which starting number, under one million, produces the longest chain? NOTE: Once the chain starts the terms are allowed to go above one million. The Solution: We can divide the solution in 3 task. To form the chain of sequence. To feed the data to the first function. Third will be sort the values.  To form the chain of sequence: def chain(n):        a = []  # will hold the sequence     a.append(n)     while n...
Post a Comment
Read more

Project Euler 11: What is the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20×20 grid?

You guys can get this programming ask from Project Euler. This  is the 11th question  of this series. The solution of this question needs you to be good in matrix. You can find the solution below. The Solution: You have to find the greatest product of the four adjacent number and the number can should be in the same direction. So basically, if we start by first number of the series 08; then we can find only 3 adjacent number in the same direction and that will be: 1>  08 02 22 97(going in positive direction) 2>  08 49 81 52 (Going in down direction) 3> 08 49 31 23 (Going in positive diagonal direction) but a number can have maximum 8 products in the same direction; for better understanding we have marked it in the red and you can also check the below image for better understanding. 08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08 49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00 81 49 31 73 55 79 14 29 93 71 40 67...
Post a Comment
Read more